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there are several problems, if anyone can help with all or any that would be greatly appreciated!
1. x^3-3x^2-x+3
2.x^6-2x^3+1
3. {x+4/x^2-x-2} - { 2x+3/x^2+2x-8}
4.(1/2 + sq root of 3i/2)^2
5.x^4+13x^2+36
6.2 - sq root of 5/ 2 + 3 sq root 5
7. (9/8)^3/2
8. -6/x+4
9. How many ounces of pure water should be added to 20 oz. of a 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
10. A motorboat maintained a constant speed of 15 mph relative to the water in going 10 miles upstream and than returning. the total time for the trip was 1.5 hours. use this info. to find the speed of the current.
11. In the 1984 olympics, Carl Lewis won the gold metal in the 100 meter race w/ a time of 9.99 seconds. 1896, Thomas Burke won the gold metal in the 100 meter race in 12.0 seconds. If they ran the same race, repeating their respective times, by how many meters would Lewis beat Burke?


THANK YOU GUYS SOOO MUCH!!!!

2007-10-03 12:06:57 · 3 answers · asked by shortycowgrl101 1 in Science & Mathematics Mathematics

3 answers

Hate to tell you this, but we're not going to do your homework for you. Now, if there's some specific thing that you don't understand, we'll be happy to help you out, but you should try to work the problems on your own first. Besides, doing your own homework has been known to greatly improve understanding, and in fact you could have been halfway through in the time that it took you to type this into Y!A.

2007-10-03 12:13:20 · answer #1 · answered by Pascal 7 · 0 0

#11: Burke ran 100 meters in 12 sec. Divide 100 by 12 to get his meters per sec. (8.33333333333333333333). Multiply this number by the time it took Lewis to win (9.9) and you have how many meters Burke had run when Lewis finished (82.5). To find out how many meters Lewis beat Burke by take 100 and subtract 82.5 (17.5 meters).

2007-10-03 12:36:03 · answer #2 · answered by stephie_00 3 · 0 0

You can't expect people to do all this for you. If your that stumped about a subject you took last year, ask about the individual concepts or look it up in your books. That's pretty basic stuff, don't get lazy.

2007-10-03 12:10:03 · answer #3 · answered by Anonymous · 0 0

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