A gold ball with an initial angle of 24 degrees lands exactly 240 m down the range on a level course?

Question

A)Neglecting air friction, what initial velocity would achieve this result?


B)Using the initial velocity found in item a above, determine the maximum height reached by the gold ball.


please help me genius people! i'll appreciate it forever!!

Answer 1

A. Initial velocity v0 = sqrt(range*g/sin(2theta))
B. v0y = v0*sin(theta)
ymax = v0y^2/(2g)
See the ref. for derivation of these equations.