I have a question that asks the lengths of a triangles sides. The length of the hypotenuse is 130 cm, and the area is 3m. Is there a relation between this and its side lengths? How can I figure this out? The answer is 120 x 50, but I need to know how to get to this.
2007-10-03 11:34:57 · 3 answers · asked by Marie 2 in Science & Mathematics ➔ Mathematics
Tan, how did you get xy = 30000?
2007-10-03 11:49:46 · update #1
By Pythagoras' theorem, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
So let's take the length of the two sides to be (x)cm and (y)cm respectively,
x^2 + y^2 = 130^2 = 16900
xy = 30000
Solve these simultaneous equations and you get 120 and 50.
2007-10-03 11:39:02 · answer #1 · answered by Tan Z 3 · 0⤊ 0⤋
If you are told that you have a right triangle then you know that hypotenuse squared = sum of the square of the legs.
5-12-13 is a well-known Pythagorean triple because 13^2 = 5^2 +12^2
So 130^2 = 120^2 + 50^2 <-- 10 times the 5-12-13 triple.
2007-10-03 11:44:43 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
nicely, the altitude divides the triangle into 2 top triangles. you need to use trigonometry, on the grounds which you know the angles of the nicely suited triangle are 30, 60 and ninety stages. or you need to use the Pythagorean theorem, on the grounds which you know that the fast edge is a million/2 the hypotenuse (no trig mandatory).
2016-12-28 13:27:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋