You mean in general, or is there some specific diagram you're supposed to be looking at? Certainly, it is not the case in general that supplementary angles form a linear pair -- consider angles ∠ABC and ∠DEF, where B≠E. These angles don't even share a vertex, and thus cannot possibly be a linear pair, although they certainly might be supplementary. Even the supposition that ∠2 and ∠3 share a common side is insufficient. Consider, in the following diagram, let ∠2 = ∠AOB and ∠3 = ∠AOC:
C .......B
\ ......./
.\ ...../
...\ ../
....\/________A
... O
Notwithstanding the inaccuracy of the drawings, ∠AOC and ∠AOB are supplementary and share a common side, but do not form a linear pair. So unless there is some diagram showing that ∠2 and ∠3 share a common side AND that that side is between the other two rays, this conjecture is blatantly false.
2007-10-03 11:14:52
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answer #1
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answered by Pascal 7
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Jon will score on the next play. the grass will grow. he got a haircut by jim. It's valid. it's valid. it's invalid. it's invalid. 8) true 9) false. The two can be opposite each other in a quadrilateral. 10) false. The two angles can be C - angles. 11) false. A rhombus has four equal sides. 12) true.
2016-04-07 02:25:30
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answer #2
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answered by ? 4
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