6-9 times 4 divided 3
divided by
2 times 3
2007-10-03 10:50:28 · 7 answers · asked by HCO luva 2 in Science & Mathematics ➔ Mathematics
6-9x4/3/(2x3)
6-36/3/6
6-12/6
6-2=4
or
6-9x4/3/2x3
6-36/3/2x3
6-12/2x3
6-6x3
6-18=-12
2007-10-03 11:05:04 · answer #1 · answered by Andrew 1 · 1⤊ 0⤋
6 - 9 = -3
-3 X 4 = -12
-12 / 3 = -4
-4 / 2 = -2
-2 X 3 = -6
2007-10-03 10:55:55 · answer #2 · answered by Rai 4 · 0⤊ 1⤋
I got the same answer as sweet thing...is your problem
6-9 * 4/3 all divided by 2*3...6-36/3 divided by 6...6-12 divided by 6...-6/6 = -1
2007-10-03 11:06:57 · answer #3 · answered by mago 5 · 0⤊ 0⤋
Just do each bit separately.
My answer may be wrong as your question is unclear as to whether or not it is (6-9) times (4 divided by 3) or ((6-9) times 4) all divided by 3. I'll assume you meant the former.
So, you can set it out using brackets.
((6-9)*(4/3))/(2*3)
So solve the separate brackets first.
=(-3*(4/3))/6
=-4/6
2007-10-03 11:00:10 · answer #4 · answered by Atari 2 · 0⤊ 1⤋
6 -9*4/(3*2*3) = 6-36/18 = 6-2 = 4
2007-10-03 10:56:18 · answer #5 · answered by ironduke8159 7 · 0⤊ 1⤋
6-9*4/3
6-36/3
6-12
-6
2*3= 6
-6/6=
-1
= ]
2007-10-03 10:55:37 · answer #6 · answered by Vanessa 4 · 0⤊ 0⤋
6-9*3/2*3
6-27/2*3
6-27/6
6-4.5
1.5
2007-10-03 10:57:16 · answer #7 · answered by Anonymous · 0⤊ 1⤋