A 2.00 kg block is held in equilibrium on an incline of angle = 60° by a horizontal force applied in the direction of the increasing incline. If the coefficient of static friction between block and incline is µs = 0.300, determine the following.:
(a) the minimum value of force/vector F: ____ N
(b) the normal force exerted by the incline on the block: ____ N
Would somebody kindly show me how to do this, step by step, and show your work and the answer? I'm stuck.
2007-10-03 09:23:36 · 1 answers · asked by justme 4 in Science & Mathematics ➔ Physics
Sorry, but those answers are coming back wrong.
2007-10-03 10:07:24 · update #1
The force must counter act the gravity parallel to the incline less the force of friction if friction is insufficient to hold it
Normal force is
N=cos(60)*2*9.81
=9.81
F+N*µs>=sin(60)*2*9.81
F>=17-9.81*0.3
F>=14 N
j
2007-10-03 09:44:26 · answer #1 · answered by odu83 7 · 0⤊ 0⤋