At x=5, and equation to the line tangent to the graph of f(x)=60(sqrt(169-x^2)/(x)) is y=?

Question

It should be in the form y=mx+b.

Answer 1

The slope of the tangent line is given by the value of the derivative at x = 5. The point has x coordinate 5 and the y coordinate is found by evaluating the function at x = 5. You can then find the equation of the line by the point-slope method, and then converting the equation to slope-intercept form.