i'm poor in math.. pls. help.?

Question

use synthetic division:

6x²+ 11x^5-28x^4 - 39x³ +4 6x^2 +28x - 24 ÷ 2x^3 - x^2 – 7x + 6=

8x^5 – 14x^4y - 13x^3 y + 16x^2 y + 5xy^4 – 2y^5 ÷ 4x^2 + 3xy – y^2 =

2x^6 – 3x^4 – x^2 + 2x – 3 ÷ x^3 – 2x^2 + x – 3=

3x^5 – 2x^3 + x – 1 ÷ 2x + 1=


well.. i don't know how to do it...can smbody pls.. explain to me and pls. teach me how to solve this...

thnx in advance..

don't answer if uu don't know it...

a lesson from secondary level

Answer 1

Okay, jean, I can help, but I think you have some misprints. I believe your first problem is (6x^6 + 11x^5 - 28x^4 - 39x^3 + 46x^2 + 28x - 24)/(2x^3 - x^2 - 7x + 6. The quotient is 3x^3 + 7x - 4, and here is how you find it. [You are going to be using 2x^3 (the leading term in the divisor) to get each term in the quotient.] Decide what the leading term 6x^6 is when divided by 2x^3; the result is 3x^3, and that is the FIRST TERM of your quotient. Now multiply the divisor by the FIRST TERM: you get 6x^6 - 3x^5 - 21x^4 + 18x^3, and you next subtract that from the original dividend. The result is 14x^5 - 7x^4 - 57x^3 + 46x2 + 28x - 24, and this is your new dividend.

The leading term is 14x^5; divide that by 2x^3 to get 7x^2, which is the SECOND TERM of the quotient. (Now we are going to repeat the steps we took earlier.) Multiply your SECOND TERM by the divisor to get 14x^5 - 7x^4 - 49x^3 + 42x^2, which you subtract from the latest dividend. The result is - 8x^3 + 4x^2 + 28x - 24, and that is your new dividend.

Repeat. -8x^3 divided by 2x^3 is -4. Multiply -4 times the divisor to get -8x^3 + 4x^2 + 28x - 24. Subtract that from your last divident, and get 0. You are through.
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There is also a misprint in your second problem. It should be 8x5 - 14x^4y - 13 x^3y^2 + 16 x^2y^3 + 5xy^4 -2y^5 divided by 4x^2 + 3xy - y^2. As before, we will use 4x^2 on the leading term of the dividends to find terms in our quotuent. 8x^5/4x^2 = 2x^3, which is the FIRST TERM of the quotient. Multiply the divisor by 2x^3 to get 8x^5 + 6x^4y - 2x^3y^2. Subtract that from the dividend to get the new dividend -20x^4y - 11x^3y^2 + 16x^2y^3 + 5xy^4 - 2y^5.

Divide -20x^4y/4x^2 = -5x^2y, the SECOND TERM of the quotient. Multiply the SECOND TERM by the divisor = -20 x^4y - 15x^3y^2 + 5x^2y^3. Subtract that from the previous dividend to get the new dividend of 4x^3y^2 + 11x^2y^3 + 5 xy^4.

Divide 4x^3y^2 by 4x^2 = xy^2. Multiply that by the divisor to get 4x^3y^2 + 3x^2y^3 - xy^4, and subtract that from the previous dividend to get the new dividend of 8x^2y^3 + 6xy^4 - 2 y^5.

Divide 8x^2y^3/4x^2 = 2y^3, the THIRD TERM of the quotient. Multiply 2y^3 by the divisor to get 8x^2y^3 + 6xy^4 - 2y^5. Subtract this from the last dividend, get 0, and quit.

Either there are more misprints in the other two, or you have been asked to take a giant step in understanding. I can't tell which.

Answer 2

6x2 is 6 to the 2 ond power which is 36.
you need to get the book
what I forgot about math....its in all book stores

Answer 3

Yipes! Get a math tutor!

Answer 4

sry cant help but i can give you this
http://www.calculator.com/
i found this helped me when i was in mathematics trouble
sry im not much help but good luck sry
you should mention what grade next time

Answer 5

try using ur calculater