The distance an object falls is directly proportional to the square of the time it has been falling. After 6 seconds it has fallen 1296 feet. How long will it take to fall 2304 feet?
2007-10-02 20:19:56 · 5 answers · asked by ladygodiva89 1 in Science & Mathematics ➔ Mathematics
d = k t ²
1296 = 36 k
k = 36
t ² = 2304 / 36
t ² = 64
t = 8
Will take 8 seconds.
2007-10-03 07:17:42 · answer #1 · answered by Como 7 · 2⤊ 1⤋
d = kt^2
1296 = k*(6)^2 = 36k so k = 1296/36 = 36
2304 = kt^2 = 36t^2
t^2 = 2304/36 = 64
t = 8 seconds
2007-10-02 20:42:29 · answer #2 · answered by zsm28 5 · 0⤊ 1⤋
let 'd' be the distance of the falling object.
let 't' be the time taken by the object.
given : d is proportional to t^2 (t^2 means t square)
i.e. d/t^2 = constant, k(say)
d1/t1^2=d2/t2^2
2304/t^2=1296/36
calculate it your self i think u will get the answer.
2007-10-02 20:41:33 · answer #3 · answered by jai18 1 · 0⤊ 0⤋
it is very simple one just form two equatins n elmintae the constant
and also u can use the 3 basic equation of linear motion of physics
2007-10-02 21:09:47 · answer #4 · answered by saurabh pareek 2 · 0⤊ 1⤋
6/1296
x/2304
1296x=6*2304
x=13824/1296
it falls for 10.66 secs
2007-10-02 20:36:46 · answer #5 · answered by theintimadator85 1 · 0⤊ 0⤋