since slope is -4, m = -4 and you have y = -4x + b. to get b, plug in -3 for x and 2 for y:
2 = -4(-3) + b
2 = 12 + b
-10 = b
so y = -4x - 10
2007-10-02 18:58:38
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answer #1
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answered by Philo 7
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i'm going to tell you the thank you to do it so as which you will locate the respond on your guy or woman. If that's no longer what you're searching for, sorry: First, you will desire to locate the slope (m). Slope = upward thrust over run, or exchange in y over exchange in x (exchange in y divided by using exchange in x). The exchange in y is the exchange interior the y values, so subtract those. The exchange in x is the exchange interior the x values, so subtract those, yet basically remember to maintain the 1st element an identical for each operation. as quickly as you have m, all you will desire to do is remedy for b. you're equation is now y= mx +b (b is unknown). to remedy for b, use the two of the criteria you're given (a million,2) or (-3,6), and plug the x and y fee into your equation. as a results of fact which you already understand m, you will desire to get a solution for b. as quickly as you have that, exchange that back into your equation with m, and you will desire to have your answer.
2016-10-10 05:16:46
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answer #2
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answered by ? 4
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y=mx+b whereby m is your gradient of the slope and b is your y-intercept.
Subt x= -3 and y =2 and m = -4 into the equation and u get
2=(-4)(-3)+b
2=12+b
-10=b
Subt the b back to the original equation format,
you'll get
y= -4x -10
2007-10-02 19:02:28
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answer #3
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answered by BretHitmanHart 1
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Hai Boo Radley,
Philo has already answered this correctly.
I am just trying to help you understand the concept.
The equation y = mx +b, is the standard equation for a straight line.
In the equation, x = x co-ordinate of any point on the line.
y = y co-ordinate of the point corresponding to x
m = (y1 - y2)/(x1 - x2) = slope of the line .....(x1, y1) & (x2, y2) being any two points on the line
Here, x & y are variables.
m & b are constants for a particular straight line.
If you know the constants m & b, you can find the points on the straight line by assuming value for x(or y) and finding the value of corresponding y (or x)using the equation. By finding any two points, you can plot the line on a graph sheet.
2007-10-02 19:13:28
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answer #4
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answered by WishInvestor 3
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m is slope
x and y are given as the point where x=-3 and y=2
now plug into the equation and solve for b to get all the unknowns. Like this:
y=mx+b
2=(-4)(-3)+b
b= -10
the equation becomes:
y = -4x -10
2007-10-02 19:03:01
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answer #5
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answered by 037 G 6
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Stay away from my mockingbirds, Ms. Radley.
Since m=the slope, m=-4. Now the problem is to find b. To do this, we substitute in for x and y the values -3 and 2, respectively. This gives us
2= -4(-3) + b, from which b=-10
So the answer is y = -4x-10
2007-10-02 19:02:09
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answer #6
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answered by cattbarf 7
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slope is -4 means that m=-4, then just plug in (-3,2) for x and y to find out what b is
2=(-4)(-3) + b
2=12+b
b= -10
so y = -4 x - 10 is the final equation
2007-10-02 19:00:51
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answer #7
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answered by Jason P 2
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START WITH
y = mx + b
M=SLOPE
y = mx + b
y = (slope) x + b
y = -4x + b <<< KEEP
SOLVE FOR B USING (-3,2)
(-3,2) = (x,y)
y=-4x+b
2= -4(-3) +b
2=12+b
b= -10 <<<< PUT INTO EQUATION
y= -4x - 10 < equation with SLOPE of -4 and goes through (-3,2)
2007-10-02 19:01:57
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answer #8
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answered by Anonymous
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to find the y intercept just plug the point into y and x. then m=-4
2=-4(-3)+b
2=12+b
-10=b
now just plug that sucker in there.
y=-4x-10
2007-10-02 19:02:14
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answer #9
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answered by Anonymous
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