how do i graph 3x-2y<8 as a inequality?

Question

i have the answers 8/3 ,5 ,5. I want to know how could i get those answers i try but dont undestrand it

Answer 1

If you can graph a straight line, you can graph an inequality!
After graphing the line, there are only two additional steps to remember.
(1) Choose a point not on the line and see if it makes the inequality true. If the inequality is true, you will shade that side of the line -- thus shading over the point. If it is false, you will shade the other side of the line -- not shading over the point.
(2) If the inequality is less than or equal to or greater than or equal to, the line is drawn as a solid line. If the inequality is simply less than or greater than, the line is drawn as a dashed line.

Solve the equation for y (if necessary).
2. Graph the equation as if it contained an = sign.
3. Draw the line solid if the inequality is or
4. Draw the line dashed if the inequality is < or >
5. Pick a point not on the line to use as a test point.
The point (0,0) is a good test point if it is not on
the line.
6. If the point makes the inequality true, shade that
side of the line. If the point does not make the
inequality true, shade the opposite side of the line.

Answer 2

I don't understand answer, but can explain how to graph the inequality.
3x-2y<8
=> y > (3/2)x - 4

All you have to do is draw the line with slope 3/2 and having y-intercept 4.

The graph of inequality is the region below this line.

Answer 3

plot the x and y intercepts of the boundary LINE, 3x - 2y = 8:

when y = 0, 3x = 8, x = 8/3
when x = 0, -2y = 8, y = -4

since the inequality is <, not ≤, draw a dotted line through (8/3,0) and (0,-4)

test (0,0) in the inequality:
3(0) - 2(0) = 0 < 8 is true, so shade the side of your dotted line that contains the origin, (0,0).

Answer 4

3x - 2y < 8
-2y < -3x + 8
y > (3/2)x - 4

for a graph, go to www.quickmath.com, click on plot under Inequalities and it will graph it for you.