2007-10-02 16:52:27 · 7 answers · asked by chyla212 1 in Science & Mathematics ➔ Mathematics
OK
x + x + 1 =51
2x +1 =51
2x =50
x=25
The two numbers are 25, and 26.
Hope that helps!
2007-10-02 16:55:53 · answer #1 · answered by pyz01 7 · 0⤊ 0⤋
Consecutive is continuing.Integer is whole number.
51 - 1 = 50
50 / 2 = 25 ( the smallest number )
25 + 1 = 26 ( the biggest number )
The two numbers are 25 and 26 .
2007-10-02 17:03:59 · answer #2 · answered by T 2 · 0⤊ 1⤋
First type: x 2d type: x+2 entire: 104 We take each and each "integer" and upload them jointly: x+x+2=104 upload like words jointly and subtract 2 from the two sides: 2x=102 Divide 2 from the two sides: 2x/2=102/2 x=fifty one we've the 1st integer, yet we could desire to locate the different integer, we merely subtract fifty one from 104: 104-fifty one=fifty 3 the two consecutive unusual integers which will upload as much as 104 are: fifty one and fifty 3. answer: fifty one, fifty 3
2016-11-07 03:00:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Let N = first number
Let N + 1 = second number
N + (N+1) = 51
2N = 50
N = 25
N+1=26
2007-10-02 16:56:25 · answer #4 · answered by Mαtt 6 · 0⤊ 0⤋
let x=first num
x+1=2nd num
x+x+1=51
2x=51-1
2x=50
x=25
x+1=25+1=26
2007-10-02 17:01:29 · answer #5 · answered by ptolemy862000 4 · 0⤊ 1⤋
n + (n+1) = 51
2n = 50
n = 25
n+1 = 26
2007-10-02 16:55:57 · answer #6 · answered by ecolink 7 · 1⤊ 0⤋
x + (x+1) = 51
2x + 1= 50
2x=50
x= 25
25, 26
2007-10-02 16:56:14 · answer #7 · answered by Frustrated 2 · 0⤊ 0⤋