A 0.700 kg ball is on the end of a rope that is 1.20 m in length. The ball and rope are attached to a pole and the entire apparatus, including the pole, rotates about the pole's symmetry axis. The rope makes an angle of 70.0° with respect to the vertical. What is the tangential speed of the ball?
2007-10-02 16:34:15 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Using the centripetal force of
f=m*v^2/r
this is counterbalanced by the horizontal component of rope tension:
m*g*sin(70)
r=1.2*sin(70)
therefore
using g=9.81
v=sin(70)*sqrt(1.2*9.81)
v=3.22 m/s
j
2007-10-03 11:03:43 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
Centripetal acceleration = V^2/R = 3 => v^2=9 => V = 3m/s a) The circumference = 6pi meters. At 3m/s it takes 6pi/3 s per revolution = 2pi seconds/rev Or 2pi seconds per 2pi radians or a million radian/sec b)
2016-10-10 05:08:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋