Graph the quadratic equation after completing the given table of values. y = x^2 – 2x?

Question

Graph the quadratic equation after completing the given table of values. y = x^2 – 2x

x y
-1
0
1
2
3

Answer 1

let f(x)=x^2-2x
f(-1)=
f(0)=0
f(1)=-1
f(2)=0
f(3)=3

also
y+1=x^2-2x+1
(y+1)=(x-1)
therefore the vertex of the parabola is at 1,-1
and the parabola opens upward
the axis of symmetry is at
x=-b/2a=-(-2)/2(1)=1

Answer 2

First put it into standard y = a(x-p)^2 + q form y = x^2 + 2x y = (x^2 + 2x) 2/2 = 1 1^2 = 1 y = (x^2 + 2x + 1 - 1) y = (x^2 + 2x + 1) -1 y = (x+1)^2 - 1 This equation is congruent to y = x^2, so make your table of values using that. The vertex is (-1, -1) so using that as your center point just graph your perabala using your table of values.

Answer 3

y = x (x - 2)

x----------- -1__ 0__ 1__ _2_ _3
(x - 2)___-3_ - 2_ - 1__ 0_ _1
y------------3__0___-1___0__3

Points for graph are:-
(-1,3) , (0,0) , (1,-1), (2,0) , (3 , 3)
Draw graph.