Math question?

Question

(y^5)^3 (y^3)^2 / (y^4)^4

Answer 1

When there is an exponent outside an exponent you multiply them. For example (2^3)^2 = 8^2 = 64 This is the same as 2^6 or 2x2x2x2x2x2 = 64.

So...

(y^5)^3 = y^15
(y^3)^2 = y^6
(y^4)^4 = y^16

When multiplying common variables with exponents, you add the exponents, if you divide you subtract

y^15*y^6/y^16 = y^21/y^16 = y^5

Answer 2

(y^5)^3 (y^3)^2 / (y^4)^4=

(y^15)(y^6) / (y^16)=

y^21 / y^16 = y^5

Answer 3

(y^5)^3 (y^3)^2 / (y^4)^4

When you take the exponent of an exponent you can just multiply them together, so you would get:

y^15 y^6 / y^16

When they are multiplied and divided you can add / subtract the exponents (since you are taking the exponents of the same base). So you would get:

y^(15+6-16)

Which is:

y^5

Now, I've probably given away the answer to your homework, but please at least read the explanation and try to learn why. If you are having problems try to ask your math teacher after class. (and if your math teacher is really bad, ask one of the other teachers at your school!)

Answer 4

(y^5)^3 (y^3)^2 / (y^4)^4
= y^(15+6-16)
= y^5
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Ideas: Since you have the same base, you just collect all the exponents.

Answer 5

= y^15*y^6/y^16
=y^21/y^16
=y^5

Answer 6

(y^5)^3=y^15
(y^3)^2=y^6
(y^4)^4=y^16

multiply the powers together when they are like this

add when they are like this
y^15*y^6=y^21

subtract 21-6 when you are dividing
(y^21)/(y^16)=y^5

Answer 7

(y^5)^3 (y^3)^2 / (y^4)^4

Recall that (y^a)^b = y^(a*b)
y^15 * y^6 / (y^16)

Recall that y^a * y^b = y^(a+b)
y^21 / y^16

Recall that y^a / y^b = y^(a-b)..
That's the numerator's exponent minus the donominator exponent!

y^5

Good luck!

Answer 8

(y^21)/(y^16) which is y^5