How to solve this equation, Thanks.?

Question

Please , help me , I think it foer a day, but I cannot solve it.
the square root of (6^2+x+7)subtract the square root of (3x+2) = 2

Please , help me , I think it foer a day, but I cannot solve it.
the square root of (6^2x+x+7)subtract the square root of (3x+2) = 2

Please , help me , I think it foer a day, but I cannot solve it.
the square root of (6x^2+x+7)subtract the square root of (3x+2) = 2

Answer 1

as i read it
sqrt(43+x) -sqrt(3x+2)=2
1) x>=-43
sqrt(43+x)=2+sqrt(3x+2)
square both sides
43+x= 4+3x+2 +4*sqrt(3x+2)
37-2x=4 sqrt(3x+2)
37-2x>=0 so x<= 37/2
square again
1369-148x+4x^2 =48x+32
4x^2-196x-1337 =0 which is a 2nd degree equation you can solve.
Verify -43<=x<=37/2
If you wrote it wrong,in any case this is the method