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solve ln(9 + lnx) = -9 for the variable x

the answer I get seems kind of strange

2007-10-02 14:34:53 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

I got about 1.4729

Or you can try yourself at answering my question:
http://answers.yahoo.com/question/index;_ylt=Amm2xFBBZDtYvvaci5ORr0fsy6IX;_ylv=3?qid=20071002162711AARaG1s

2007-10-02 14:43:59 · answer #1 · answered by poicool55 2 · 0 0

Yep, this will be one messed up answer ;)

Lets errr... exponentiate both sides (ie as index of e)

e^(ln(9-lnx)) = e^-9
9-lnx = e^-9
ln x = 9 - e^-9
x = e^(9 - e^-9)

So yeah, that is a pretty awkward answer. Why not plug it into your calc and see if it works?

2007-10-02 21:41:59 · answer #2 · answered by mevelyn2551 3 · 0 0

9+ln x > 0 so x> e^-9
now 9+ln x= e^-9 so lnx= e^-9-9 and x= e^(e^-9)/e^9

2007-10-02 21:43:50 · answer #3 · answered by santmann2002 7 · 0 0

It's strange in a better way than in my math book. Mine always says things like TUNAFISH for an answer, and the teacher thinks it's funny so we all have to pretend, since she would lower our grades if we didn't.

2007-10-02 21:44:24 · answer #4 · answered by ♥katie♥ 4 · 0 0

e^-9=9+lnx
e^(e^-9 -9)=x
2.7182718^(-8.999876)=x
x=0.0001234

2007-10-02 21:54:10 · answer #5 · answered by doober 1 · 0 0

TRY IT ON A CALCULATOR I BET ITS RIGHT

2007-10-02 21:41:08 · answer #6 · answered by Jahmila E 1 · 0 0

willie nelson

2007-10-02 21:45:20 · answer #7 · answered by bubba gumps light 3 · 0 0

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