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A 250 kg log is pulled up a ramp by means of a rope that is parallel to the surface of the ramp. The ramp is inclined at 30.0° with respect to the horizontal. The coefficient of kinetic friction between the log and the ramp is 0.800, and the log has an acceleration of 0.700 m/s2. Find the tension in the rope

2007-10-02 13:46:47 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Now just for fun T- the force needed to overcome force of friction and downward force and maintain that acceleration a
T= Fd + f + F
Fd= mg sin(30)
f=u mg cos(30)
F=ma

T=m[g(sin(30) + u cos(30)) + a]=
T=250 [ 9.81(sin(30) + u cos(30)) +0.7]=
T=3100N

2007-10-02 16:06:05 · answer #1 · answered by Edward 7 · 0 0

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