Tickets for the dance cost 20 bucks for a single ticket or 35 bucks for a couple. ticket sales totaled 2280 bucks and 128 people came. how many of each type were sold?
2007-10-02 13:22:20 · 3 answers · asked by Louis C 2 in Science & Mathematics ➔ Mathematics
We'll, I couldn't answer clearly. But I know that if every ticket was 20$, there would be 114 tickets sold. I hope this helped you get a little closer to finidng the answer.
2007-10-02 13:34:54 · answer #1 · answered by Anonymous · 0⤊ 0⤋
let S be the number of single tickets sold
let C be the number of couple tickets sold
total money collected = 20xS + 35xC = 2280
total people attended = S + 2xC = 128
So we have two linear equations in two unknowns. Use any of the standard methods to solve them.
For example, multiply the second equation by 20 to get:
20xS + 40xC = 20 x 128 = 2560
Subtract the two equations to get:
(20 - 20) x S + (40 - 35) x C = 2560 - 2280 or
0 x S + 5 x C = 280
since 0 x S is 0, dividing by 5 gives C = 280/5 = 56
substituting, we have:
S + 2xC = 128 = S + 2 x 56 = S + 112
subtract 112 from both sides to get S = 16
next, we check
16 + 2 x 56 = 128 - correct
20 x 16 + 35 x 56 = 2280 - correct
2007-10-02 21:35:17 · answer #2 · answered by simplicitus 7 · 0⤊ 0⤋
divide...it might help
2007-10-02 20:30:32 · answer #3 · answered by l c 1 · 0⤊ 0⤋