Gravitational force: Fg= Gm1m2 / (D)^2 Fg= gravitational force. G= gravitational constant = 6.67 x (10^-11 N.m^2/kg^2) m1= mass of one object m2= mass of other object d= distance between the two masses.
Cavendish, in his experiment to determine "G" suspended a mass of 167 kg at a distance of 0.200 m from a mass of 0.800 kg. If the force of attraction as indicated on the scale of his torsion balance was 2.23 x 10^-7 N, what value did he get for "G".
Determine the distance of seperation of two 10.0 kg masses in outer space if the gravitational force of attraction between them is 5.50 x 10^-8 N.
While picking up moon rocks on the moon, the Berenstain Bears wanted to determine the mass of a particular rock, but they had no equipment for weighing objects. They did know however that the mass of the moon is 7.34 x 10^22 kg and the radius of the moon is 1.74 x 10^6m and using their Newton sprint scale, they found the weight to be 77.6 N. What is the mass of this particular rock.
2007-10-02
12:24:03
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3 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Physics
I basically need help rearranging the original equation to solve for other variables such as m1, m2, G and d, please show as many steps as possible for me to understand thanks. More questions are:
3. What is the force of gravity on the Earth's surface on each of the following masses?
a) 75.0 kg
b)350 kg
c) 4.25 t note t = 1000kg
4. How would you determine the weight of each mass in question 5?
5. Determine the mass of the following objects, if their weigth on Earth is given.
a) 0.50 N
b) 30 N
c) 2900 N
6. Two equal 20 kg masses in outer space have a gravitational attraction of "x". If you wanted to double the force of gravitational attraction between them, how much closer would they have to be?
Please show work Thanks :)
2007-10-02
12:27:33 ·
update #1