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1. y = 2x and y=2x - 4

2. 2y + 3x = 5, 3y - 2 x 5

3. 1/3x + 2/3y = 3/5 and 2x + 4y = 7

4. 2y + 3x = 5 and 3y + 3x = 5

The help would be appreciated.

2007-10-02 12:23:08 · 4 answers · asked by PIMP I 1 in Science & Mathematics Mathematics

4 answers

Two lines are parallel if their slopes are the same.
Two lines are perpendicular if their slopes are negative reciprocals of each other.

So get each pair of lines in the form of y = mx + b. Then you can compare the slopes (m).

2007-10-02 12:27:06 · answer #1 · answered by Anonymous · 2 1

Two line are parallel if they have the same slope AND have different y-intercepts.

Two lines are perpendicular if the product of their slopes = -1.

1) lines are ||
2) y= -3/2x +5/2 and y = 2/3x +5/3 so _|_
3) y = -x/2 +9/10 and y = -x/2 +7/4 so ||
4) y = -3x/2+5/2 and y = - x +5/3, so neither

2007-10-02 12:45:56 · answer #2 · answered by ironduke8159 7 · 0 0

First, you may desire to place the lines in slope-intercept kind, this is y = mx + b the place m is the slope and b is the y-intercept. x = (–17/11)y + (219/11) 11x = –17y + 219 11x + 17y = 219 17y = –11x + 219 y = (–11/17)x + (219/17) 17x + 11y = 33 11y = –17x + 33 y = (–17/11)x + 3 Parallel lines have a similar slope yet distinctive y-intercepts...the slope isn't a similar, so as that they are no longer parallel lines. Perpendicular line have slopes that are unfavorable reciprocals of one yet another...those are purely reciprocals of one yet another, yet no longer unfavorable reciprocals of one yet another. So the respond is neither.

2016-12-28 11:52:48 · answer #3 · answered by ? 4 · 0 0

1 Parallel, a simple factor was added

With 2, 3, and 4; I would rewrite them and solve for Y and see what I have.

2007-10-02 12:35:56 · answer #4 · answered by RichardPaulHall 4 · 0 0

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