angle CDB= (8y+8)degrees. angle BDA = (5y-3)degrees, and angle ADC= 70 degrees.
find angle CDB and angle BDA
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2007-10-02 11:25:15 · 5 answers · asked by bhattigirl23 2 in Science & Mathematics ➔ Mathematics
It helps if you draw a picture...
2007-10-02 11:33:55
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answer #1
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answered by Anonymous
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(8y+8)+(5y-3)=70
13y+5=70
13y=65
y=5
Plug in 5 for y for each angle
So,
well, lets say that the angle ADC is the biggest angle:
than angle ADC (70) would equal angle BDA (5y-3) plus angle CDB (8y+8), so:
70 = 5y-3 + 8y +8
70 = 13y +5
65 = 13y
y = 5
now you can find angle CDB by writing y as 5: 8y+8= 8*5+8=40+8= 48
and angle BDA : 5y-3= 5*5-3= 25-3 = 22
2007-10-02 18:42:37 · answer #2 · answered by Inbal L 1 · 0⤊ 0⤋
angle CDB + angle BDA = angle ADC = 70
so 8y+8 +5y-3 = 70
13y +5 = 70
13y = 65
y = 5
So angle CDB = 8(5) + 8 = 48 degrees
angle BDA = 5*5 -3 = 22 degrees
2007-10-02 18:35:45 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
Well, if you draw out the figure, youll see that CDB + BDA = ADC
So, then you're left with.....
(8y + 8) + (5y - 3) = 70
13 y + 5 = 65
13y = 65
y = 5
CDB = 8y + 8 = 8(5) + 8 = 40 + 8 = 48
BDA = 5y - 3 = 5 (5) - 3 = 25 - 3 =22
48 + 22 = 70
2007-10-02 18:41:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
To solve this problem, i need a picture of the shape labeled with the letters.
2007-10-02 18:33:31 · answer #5 · answered by elly_the_rocker 2 · 0⤊ 0⤋