I need help with this geometry problem. Which postulate would it be???

Question

Sketch the following.
Let a and b be two inetrsecting lines that intersect at X.
There is a point Y,distinct from X, on a line a and a point Z,distinct from X,on line b.

Which postulate allows your to conclude that there is exactly one plane that contains X,Y,Z

Answer 1

I'm not sure how your text numbers the postulates, but the one you're looking for has to do with the fact that a plane is defined by three noncollinear points in space. If the points are collinear (i.e. on the same line), that doesn't help to define a distinct plane, since the three points are on a line and you can draw many different planes through that line. On the other hand, if you have three noncollinear points, you can only draw one plane that can encompass those three points. That's why the description that you gave went through the trouble of saying that the points are distinct and on different lines.

Answer 2

it fairly is not to any extent further as annoying because of the fact it sounds. this is what's occurring H_____________J____________K you do not ignore that from KH=ninety six (so it fairly is the comprehensive distance) what you're goinna try this is a customary equation. HJ+JK=HK now substitute this with the values you have 5x+7x=ninety six now combine like words 12x=ninety six now in elementary terms freshen up for x dividing via using 12 x=8. you're even with the reality that now not executed yet. now which you stumbled on your x in elementary terms plug it in so as which you will hit upon what the size is for each section. HJ=5x HJ=5(8) HJ=40 JK=7x JK=7(8) JK=fifty six