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Ok the equation is x^2+3=2x

As an answer i got 2(+)(-)2i sqrt 2 / 2. When I simplify it i get, 1(+)(-)i sqrt2 .

Is this is the right answer? How do I check? Please help. Thanks in advance.

2007-10-02 11:02:08 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

x^2+3=2x
x^2-2x+3=0
x=[2+/-sqrt(4-12])
=]2+/-2isqrt(2)]/2
=1+/-isqrt(2).ANS.
your answer is correct.
for checking, find the sum and product of the roots, these should be 2&-3. or put the roots ,in turn, in the equation and see if the original equationis satisfied..

2007-10-02 11:13:32 · answer #1 · answered by Anonymous · 0 0

If you are correct, then (x-1+isqrt(2))(x-1-isqrt(2)) = x^2-2x+3
So x^2 -x -ixrt(2) -x+1 +irt(2) +ixrt(2) -irt(2) -2i^2 = x^2 -2x+3
Yep. You are right.

2007-10-02 11:21:22 · answer #2 · answered by ironduke8159 7 · 0 0

I believe your answer is correct. See attached website for explaination. I believe they do a good job of walking you through the process.
http://www.purplemath.com/modules/quadform.htm

2007-10-02 11:17:10 · answer #3 · answered by Jeffrey S 2 · 0 0

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