e^(ln2) = 2
The Natural base Log "ln" is, like other logs, an "inverse exponent". Taking the log of something tells you what number you would raise the base to, in this case e = 2.7..., to get that number. For example ln(5) ~ 1.6. So I need to raise e to the 1.6th power in order to get around 5. So:
e^(ln(number)) = number
ln(e) = 1
ln(e^7) = 7
This also works with base 10:
log(1000) = 3
2007-10-02 10:27:18
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answer #1
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answered by supastremph 6
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ln has no value, it is a function. When you have ln2, the question being asked is "e raised to what power will equal 2?" since you have e raised to that number anyway, the answer is 2
2007-10-02 17:28:46
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answer #2
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answered by Eli 6
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ln is not a value, it's a function. it is natural log. ln is log with a base of e (e has a value of 2.7...). so when you raise e to the ln of something, its like saying log base e of x = ln2
which is ln x = ln 2
so x =2.
basically, the ln and the e cancel out and leave you with 2.
2007-10-02 17:35:01
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answer #3
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answered by Nilly 3
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its called a natural Logarithm. Its the same as a logarithm with a base of e. So it has no value by itself, its used like a logarithm, except that it has some special properties. You'll want to use these properties to solve your problems w/o a calculator.
e^ln(x) = x
ln(e^x) = x
2007-10-02 17:31:57
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answer #4
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answered by erikoo7 3
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ln(x) is a natural log. It can best be thought of as log base e of x. That is the functional inverse of e^x.
Just as log base 10 is the functional inverse of 10^x.
basic to any inverse is f(invf(x)) = x and invf(f(x)) = x
log base 10 (10^x) = x
10^(log(x)) = x
So e^(ln x) = x
Or e^(ln 2) = 2
2007-10-02 17:36:06
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answer #5
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answered by Peter m 5
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e^(ln2) =2
2007-10-02 17:28:18
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answer #6
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answered by xandyone 5
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