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for. ex....how could i know what is e^(ln2) ...w/o using a calculator

2007-10-02 10:25:27 · 6 answers · asked by ruby 2 in Science & Mathematics Mathematics

6 answers

e^(ln2) = 2

The Natural base Log "ln" is, like other logs, an "inverse exponent". Taking the log of something tells you what number you would raise the base to, in this case e = 2.7..., to get that number. For example ln(5) ~ 1.6. So I need to raise e to the 1.6th power in order to get around 5. So:

e^(ln(number)) = number

ln(e) = 1

ln(e^7) = 7

This also works with base 10:

log(1000) = 3

2007-10-02 10:27:18 · answer #1 · answered by supastremph 6 · 0 0

ln has no value, it is a function. When you have ln2, the question being asked is "e raised to what power will equal 2?" since you have e raised to that number anyway, the answer is 2

2007-10-02 17:28:46 · answer #2 · answered by Eli 6 · 0 0

ln is not a value, it's a function. it is natural log. ln is log with a base of e (e has a value of 2.7...). so when you raise e to the ln of something, its like saying log base e of x = ln2
which is ln x = ln 2
so x =2.

basically, the ln and the e cancel out and leave you with 2.

2007-10-02 17:35:01 · answer #3 · answered by Nilly 3 · 0 0

its called a natural Logarithm. Its the same as a logarithm with a base of e. So it has no value by itself, its used like a logarithm, except that it has some special properties. You'll want to use these properties to solve your problems w/o a calculator.

e^ln(x) = x

ln(e^x) = x

2007-10-02 17:31:57 · answer #4 · answered by erikoo7 3 · 0 0

ln(x) is a natural log. It can best be thought of as log base e of x. That is the functional inverse of e^x.
Just as log base 10 is the functional inverse of 10^x.
basic to any inverse is f(invf(x)) = x and invf(f(x)) = x
log base 10 (10^x) = x
10^(log(x)) = x

So e^(ln x) = x
Or e^(ln 2) = 2

2007-10-02 17:36:06 · answer #5 · answered by Peter m 5 · 0 0

e^(ln2) =2

2007-10-02 17:28:18 · answer #6 · answered by xandyone 5 · 0 0

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