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how would you draw a displacement time graph, velocity time graph and an accelaration graph fo a bouncing ball?

2007-10-02 09:50:22 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

The displacement is a repeated parabola, the velocity a repeated sawtooth wave, and the acceleration a repeated cycle consisting of a relatively long, small constant negative value and a short large positive value. The areas between the two parts of the acceleration cycle and the x axis are equal. The velocity sawtooth consists of a long negative-slope part that is symmetric about the x axis and a short steep positive-slope part. This wave also has equal areas above and below the x axis. If the ball is perfectly elastic, the amplitudes remain the same over time; otherwise they decay in amplitude. All the most dramatic dynamics (start of new parabola, steep section of sawtooth, short high-acceleration pulse) occur at the instant of the bounce.

2007-10-08 05:14:24 · answer #1 · answered by kirchwey 7 · 0 0

i do no longer see the acceleration/time graph, yet i will visualize it to be quite often coincided with the horizontal line a = -9.8, different than at instants t at which x = 0 and v all quickly adjustments its direction from unfavorable to useful. At those factors a > 0 and its fee is defined via a = ?v/?t = 2v(max.)/?t = 2?(2gh)/?t, ?t being the very short length of time (say, 0.a million 2d) wherein the ball interacts with the floor to alter its momentum from unfavorable to useful. The shorter ?t is, the better is the height of a on the acceleration/time graph.

2016-12-28 11:35:07 · answer #2 · answered by fraccola 3 · 0 0

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