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I am trying to answer sec2x = 2 / √3

I did
1/cos2x = 2/√3
√3/2 = cos2x

Then I put cos-1(√3/2) in my calculator and got a math error, what am I forgetting?

2007-10-02 07:37:48 · 1 answers · asked by biscuit.heads 2 in Science & Mathematics Mathematics

1 answers

maybe you have to push 2ndF or something alike to get Arc cos x
Normally cos x and cos^-1 x are at the same place
2x = pi/6 so x = pi/12

2007-10-02 07:47:30 · answer #1 · answered by santmann2002 7 · 0 0

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