Hmm Easiest Way ?
Divide the Hexagon in equal size triangles.
Find the area of the triangle using 0.5*base*hight
Multiple the area of triangle to the number of triangle.
this should work.
2007-10-02 07:29:36
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answer #1
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answered by Sandip P 2
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Area Of A Hexagon
2016-09-27 20:50:25
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answer #2
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answered by ? 4
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If it is a regular hexagon, then it will divide in to '6' regular equilateral triangles.
As the base of the triangle is known say '3' and the angle is 60 degrees (equilateral triangle) then area of triangle is+
A = abSinx
Were 'a' and 'b' are two sides '3' each and 'x' is 60 degrees.
A = 3 x 3 x Sin60
A = 9 x 0.866025 = 7.79423
multiply by '6' (as there are six triangles internal to the hexagon).
7.79423 x 6 = 46.76537
A general equation is
A(hexagon) = 6abSinx
2007-10-02 07:35:13
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answer #3
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answered by lenpol7 7
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If it is a regular hexagon, it can be divided into 6 equilateral triangles with the shared endpoint in the center.
Simply use the formula to calculate the area of an equilateral triangle (http://www.mathwords.com/a/area_equilateral_triangle.htm,) using the length of one of sides of the hexagon as the value for the side of the triangle and multiple the result by 6.
2007-10-02 07:43:47
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answer #4
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answered by new yorker 2
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This Site Might Help You.
RE:
how to find the area of a hexagon?
2015-08-07 01:51:20
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answer #5
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answered by Anonymous
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Well, it's 6 equal sides with equal angles. How about cutting the "pie" into 6 pieces, and doing 1/2 BH * 6?
B=the length of a side of the hexagon
H=the distance from midpoint of B up to the middle
I guess it depends on what info you have, though. You could look at the hexagon as a rectangle and 2 triangles.
2007-10-02 07:30:20
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answer #6
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answered by Left Bank Hook 4
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Area equals=base mutilpyed by hight
2014-03-09 15:10:50
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answer #7
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answered by Meghan 1
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--->> Tips---> https://trimurl.im/e37/how-to-find-the-area-of-a-hexagon
2015-08-04 07:40:49
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answer #8
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answered by ? 1
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Break it into sections, its two triangles and a square
2007-10-02 07:29:27
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answer #9
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answered by Seargent Gork 3
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