English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2 answers

Since the zero of potential can be anywhere, this problem has no unique answer. From the phrasing of the question, let's take the zero of the potential at d=0, 20ft below the drop point.

V = mgd, K = 1/2mv^2 where d is the distance above ground

K = mg(h-d), where d is the distance fallen

We want

mgd = mg(h-d) or d = h/2, a.k.a. 10ft

2007-10-02 07:33:14 · answer #1 · answered by supastremph 6 · 0 0

at 10 feet

2007-10-02 14:28:16 · answer #2 · answered by 1101-1001 2 · 0 0

fedest.com, questions and answers