immersion of red blood cells does not result in haemolysis in: A) isotonic acetone at 20 degrees B) hypertonic salt solution at 20 degrees C) hypotonic salt solution at 20 degrees D) isotonic salt solution at 80 degrees
thanks :)
2007-10-02 02:00:49 · 5 answers · asked by xxx 3 in Science & Mathematics ➔ Biology
I agree with misoma5.
A) doesn't matter is it's isotonic or not - it's acetone, which will lyse the cells.
B) hypertonic will cause the cells to shrink ("crenation"), not lyse.
C) hypotonic will cause the cells to lyse.
D) isotonic is OK, but it's at 80oC, so the cells will lyse
2007-10-02 02:10:00 · answer #1 · answered by gribbling 7 · 1⤊ 0⤋
I think the answer is B. Hypertonic saline will cause the erythrocytes to shrink, but not lyse. Isotonic saline at 80 degrees will denature the proteins and most likely lyse the cells. A and C will cause hemolysis.
2007-10-02 02:06:20 · answer #2 · answered by misoma5 7 · 1⤊ 0⤋
Acetone is a powerful solvent...you don't want that!
Any hypotonic solution will lyse the cells, so C is out.
And D would work well except that the temperature is way too high (80C is 176F!)
The only thing left is B. Hypotonic lyses cells, hypertonic doesn't.
2007-10-02 02:17:12 · answer #3 · answered by El Jefe 7 · 1⤊ 0⤋
B, hypertonic saline solution at 20C will cause crenation in an erythrocyte, not lysis... so that is the answer.
2007-10-02 03:13:12 · answer #4 · answered by Peter Griffin 6 · 1⤊ 0⤋
i think A is correct because all other are salt with hyper- which means high.. i will go with A
2007-10-02 02:05:40 · answer #5 · answered by king of kings 1 · 1⤊ 1⤋