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I'm sorry guys, but I just can't get this stupid question for an assignment I have due tommorow, can anyone help me ???

A block of mass m = 2.5 kg is dropped from height h = 74 cm onto a spring of spring constant k = 1400 N/m. Find the maximum distance the spring is compressed. If someone could tell me how to do this question... I would be forever greatful.

And THankyou to anyone who post!!! :)

-Sarah

2007-10-02 00:27:46 · 4 answers · asked by Sarah C 1 in Science & Mathematics Physics

4 answers

It's a bit more complicated than the previous answer, which gives the static compression but ignores the energy of the falling block. At max compression the potential energy given up by the block = the potential energy stored in the spring. The block falls 0.74 m plus the amount the spring compresses dx.
PE1 = gm*(0.74+dx) = PE2 = k*dx^2/2
This results in a quadratic in dx:
k/2*dx^2 -gm*dx -gm*0.74 = 0
Solve that and take the positive root.

2007-10-02 02:32:04 · answer #1 · answered by kirchwey 7 · 0 0

a million. until eventually now the mass touches decrease spring until eventually its examining is 0 the spring scale will study 5.8x9.8 = fifty six.eighty 4 N because of the fact earth attracts the mass with this plenty rigidity and there is not any different rigidity appearing on the mass otehr than the upward rigidity of prolonged spring. 2. spring consistent,ok of decrease spring = 23/0.021 = a million.1x10 ^2 N/m 3. the top spring scale will study 0 while the decrease scale will prepare examining equivalent to the burden of the 5.8 kg mass. enable the compression then be x m, then we've, ok x = fifty six.eighty 4 or x = fifty six.eighty 4/(a million.1x10^2) = 5.a million x 10^-2 m = 5.a million cm

2016-10-05 23:08:35 · answer #2 · answered by ? 4 · 0 0

first we have to find load acting on the spring,
= mass * acceleration
=2.5*10 (acceleration due to gravity)
=25 Newton.

maximum distance of compression = load/spring constant
=25/1400
=1/56 meter
approximately 17.85 mm !!
is this correct ?????

2007-10-02 00:56:19 · answer #3 · answered by ask_me 2 · 0 0

I am somewhat aghast that you do not have an equation for this problem. If you could give an equation, i could plug the numbers in and go, but then again, so could you. Sorry to be of such little help.

2007-10-02 00:33:07 · answer #4 · answered by Friar Tuck 1 · 0 0

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