Multiply. (4m-3n)(4m+3n)?

Question

need help, when doing this shouldnt + come before - or don't this matter when multiplying?

Answer 1

In general this kind of problems are:

(a - b)(a + b) = a^2 - b^2


So,

(4m - 3n)(4m + 3n) = [4m]^2 - [3n]^2

= 16m^2 - 9n^2

Note: The order is not important

(a - b)(a + b) = a^2 - b^2
(a + b)(a - b) = a^2 - b^2

Basically, if you expand the terms out,
the middle two terms cancel out.

(a - b)(a + b) = a^2 + ab - ab - b^2
(a + b)(a - b) = a^2 - ab + ab - b^2

Answer 2

u can change the order of the question if u want. but u can also do as it is:
(4m+3n)(4m-3n) according to property (a+b)(a-b)
=4m^2- 3n^2 in the order a^2-b^2
=16m^2-9n^2

Answer 3

Multiplication of (a-b)(a+b) is always = a^2-b^2. So in the present case result is (4m)^2 - (3n)^2 which is = 16m^2-9n^2

Answer 4

(4m-3n) X (4m+3n)
= (4m-4m-3n+3n)
= (3+3)n
= 6n

Lols? I don't know! I am primary 6 and I only know basic algebra questions.. he he he

Answer 5

(4m-3n)(4m+3n)=16m square+12mn -12mn-9n square=
16m square -9n square.

Answer 6

Use the F.O.I.L. method. (first, outer, inner, last)
+ X - = -
+ X + = +

Answer 7

use this formula: a2-b2=(a+b)(a-b)
other useful algebra formulas: (a+b)2 = a2 + 2ab + b2
(a-b)2 = a2 -2ab + b2

Answer 8

i thinks it 4mn or 0...............i only made it halfway thru algebra...............ask a nerd or geek...