Question:
P(5,0), Q(8,6), R(5,8), S(2,6). Find the area of the kite PQRS.
Pls. anwer it i need it right now please... please...
2007-10-01 22:24:09 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
for P and R, subtract the y values :
8-0=8
for Q and S, subtarct the x values:
8-2=6
A=1/2(l*w)
=1/2(6*8)
=24 square units
2007-10-01 22:31:49 · answer #1 · answered by **PiNoY YFC** 7 · 0⤊ 0⤋
the kite is composed of 4 rectangula triangle with sies equal to the half of width and length of the kite.
I can not draw the kite but try on a graduated paper
the height of the kite is 8 (half of length PR ) and the width is 6 (half of QS)
so one triangle has sides of 4 and 3
the area of the triangle is 4*3/2 =6
as you have 4 triangles the total area is 4*6 = 24
2007-10-01 22:33:27 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
PR = â[(5 - 5)^2 + (0 - 8)^2] = 8
SQ = â[(8 - 2)^2 + (6 - 6)^2] = 6
Area of kite
= (1/2) PR x SQ
= (1/2) x 8 x 6
= 24
2007-10-01 22:37:41 · answer #3 · answered by Madhukar 7 · 0⤊ 0⤋
Draw the kite...Split it into 2 triangles find the area of each triangle,Then add them.
2007-10-01 22:31:43 · answer #4 · answered by paintthiscityblack 2 · 0⤊ 0⤋