Angle___cos___sin___tan
π/3_____1/2___√3/2__√3
4π/3__ - 1/2__-√3/2__√3
sin 4π/3 = - √3/2
Signs are allocated according to:-
sin | All
---------
tan| cos
4π/3 lies in 3rd quadrant so sin 4π/3 is - ve
2007-10-01 21:15:47
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answer #1
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answered by Como 7
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First, only consider the first quadrant: 0 to Ï/2.
There are 5 special angles - 0, Ï/6, Ï/4, Ï/3, Ï/2, which respectively equals 0Ë ,30Ë, 45Ë, 60Ë, 90Ë
For sine, their values are
0, (â1)/2,(â2)/2,(â3)/2 and 1=(â4)/2
For cosine, their values are
1=(â4)/2,â3/2,â2/2,â1/2, and 0
When determining the values for other quadrants, find the reference angle from the x-axis, i.e. 135Ë uses 45Ë and 330Ë uses 30Ë. Apply the trig functions on the reference angles to fine the values.
Now use the CAST method to recall the sign for each quadrant:
S | A
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T | C
Where A means all are positive, S means only sine is positive, C for cosine, and T for tangent. Throw in a negative sign for the rest.
* Disclaimer: other methods may be introduced in your book, so it is always best to refer back to your own textbook
2007-10-01 20:20:12
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answer #2
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answered by W 3
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I remember using some kind of table for that when I was in school...
2007-10-01 20:16:08
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answer #3
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answered by Anonymous
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