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2007-10-01 19:56:20 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

- A metal is an element that easily loses electrons to form positive ions and has metallic bonds between metal atoms.
- A polyatomic ion is a molecule that has a charge on it

According to Wikipeida: http://en.wikipedia.org/wiki/Metal
"In chemistry, a metal (Greek: Metallon) is an element that readily loses electrons to form positive ions (cations) and has metallic bonds between metal atoms. Metals form ionic bonds with non-metals. They are sometimes described as a lattice of positive ions surrounded by a cloud of delocalized electrons. The metals are one of the three groups of elements as distinguished by their ionization and bonding properties, along with the metalloids and nonmetals."

According to Wikipedia: http://en.wikipedia.org/wiki/Polyatomic_ions
"A polyatomic ion is a molecule that bears ionic groups, that is, a molecule with a charge. The majority of biological compounds and inorganic species conform to this strict definition. Ordinarily however, the term refers to small collections of atoms, 3 to perhaps 50 atoms, such as many metal complexes and oxyanions such as sulfate. in Greek, the prefix poly- means "many," which to a chemist means three or more atoms."

2007-10-01 20:07:28 · answer #1 · answered by Dan S 7 · 0 0

What might you call Na? (Sodium) What might you call Na+ (Sodium ion) The addition of "ion" potential the sodium has lost an electron so it has a favorable charge. What might you call NO3-? that's polyatomic (a million Nitrogen and 3 Oxygens) in spite of the undeniable fact that it additionally has one greater electron giving it a adverse charge. you may call it a polyatomic ion. The chemical bonds between the Nitrogen and the Oxygen molecules are actually not "ionic bonds", they're molecular bonds.

2016-12-14 05:25:14 · answer #2 · answered by carra 4 · 0 0

metals and polyatomic ions... u man anions and cations? your question doesnt seem to have an answer.

2007-10-01 20:01:42 · answer #3 · answered by Daniel 3 · 0 0

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