What initial velocity is needed to throw a ball exactly 10.08m straight up?

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What initial velocity is needed to throw a ball exactly 10.08m straight up?

2007-10-01 17:40:20 · 3 answers · asked by shayma h 1 in Science & Mathematics ➔ Physics

3 answers

use this formula

Vf^2=Vi^2 + 2ad

0^2=Vi^2 + 2(-9.8)(10.08)
0 =Vi^2 - 197.568
-(Vi)^2 = -197.568
Vi^2 = 197.568
Vi = Square root(197.568)
Vi = 14.0558884 m/s

2007-10-01 17:52:52 · answer #1 · answered by JR 1 · 0⤊ 0⤋

Given, h = 10.08 m, Final velocity = 0 m/s, g = -9.8 m/sÂ²
We can use the formula, VÂ² - uÂ² = 2*a*h
0Â² - uÂ² = 2 ( -9.8) 10.08
uÂ² = 197.568
u = â197.568 = 14.06 m/s
The needed initial velocity = 14.06 m/s
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2007-10-02 03:17:10 · answer #2 · answered by Joymash 6 · 0⤊ 0⤋

v = â2ay so
v = â2*9.8*10.08 = â197.568 = 14.055888 m/s

Doug

2007-10-02 00:50:03 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋