The force required to stretch a Hooke's law spring?

Question

varies from 0 N to 33.4 N as we stretch the spring by moving one end 7.06 cm from its unstressed position.
a) Find the force constant of the spring. Answer in N/m
b) Find the work done in stretching the spring. Answer in J.

Answer 1

F=-k*x

k=F/x=33.4N/.0706m=473.087N/m

w=.5*k*x^2=1.179J



Good Luck!

Answer 2

It's 33.4 N/7.06 cm or
33.4/.076 = 439.47 N/M
The total work done is equal to the energy stored in the spring and is equal to
E = (1/2)kx² = (1/2)439..47*.076² = 1.269 J

Doug