"Marissa's car accelerates at an average rate of 2.6 m/s^2. Calculate how long it takes her car to accelerate from 24.6 m/s to 26.8 m/s."
Easy, but for some reason, I can't get it.
I've tried, but it's not working out, haha.
If you could, explain while solving, please.
Thanks!
2007-10-01 16:44:54 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
initial velocity=24.6=u( u can choose any variable for ur convenience)
final velocity=26.8=v
acceleration=2.6=a
time=?=t
by using one of the equation of motion
v=u+at
26.8=24.6+2.6t
26.8-24.6=2.6t
2.2=2.6t
therefore t=2.2/2.6
t=0.81 seconds
2007-10-01 16:51:25 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Acceleration is change in velocity per unit time. In your case, the change in velocity is 26.8 m/s - 24.6 m/s , or 2.2 m/s. Since your acceleration rate is given as 2.6 m/s^2, you just need to divide the change in velocity by the acceleration to get time.
Here's the formula.
A = dV / T
2.6 m/s^2 = (2.2 m/s) / T
factoring out gets you:
T = (2.2 m/s) / (2.6 m/s^2)
T = 0.85 s
2007-10-01 16:57:29 · answer #2 · answered by skeptik 7 · 0⤊ 1⤋
vf = vi + at
(velocity final = velocity initial + accel. * time)
therefore t = (vf - vi) / a
t = (26.8 - 24.6) / 2.6 = 0.846s
2007-10-01 16:52:35 · answer #3 · answered by kylekanos 2 · 0⤊ 0⤋
v2 = v1 + at
v2 = 26.8 m/s
v1 = 24.6 m/s
a = 2.6 m/s^2
26.8 = 24.8 + 2.6t
Solving for t = 2 / 2.6 s
2007-10-01 16:56:35 · answer #4 · answered by Sheen 4 · 0⤊ 1⤋