A block of mass 500. g is sliding on a rough surface with an initial speed of 1.4 m/s. It comes to a rest after a time of 0.70 s. What is the coefficient of kinetic friction
2007-10-01 14:38:34 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
F=f force of motion F is being apposed by force of friction f
f=uN where N=mg
F=ma
a=v/t
m(v/t)=uN
u=mv/(Nt)=mv/(mg t)
u=v/(gt)=1.4 /(9.81 x 0.70)=0.204
2007-10-01 14:44:04 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
F=ma
m=.5kg
a=1.4/.7=-2m/s^2
F=1N
Coefficient of kinetic friction * Normal force (which in this case would be just gravity) = 1
Coefficient = 1/(9.81*.5) = .204 (no units)
P.S. don't listen to those other people...
2007-10-01 21:42:55 · answer #2 · answered by jthereliable 3 · 0⤊ 0⤋
More importantly, a bus leaves the depot. 1st stop 12 get on. 2nd stop 4 get on 8 get off. 3rd, 8 on, 6 off. 4th, 11 on 18 off.
What did the bus driver have for breakfast?
2007-10-01 21:41:46 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Yeah Umm.... I suggest Google.
2007-10-01 21:42:03 · answer #4 · answered by Brianna H 1 · 0⤊ 0⤋
go to your professor =)
2007-10-01 21:40:45 · answer #5 · answered by loosejuice2 1 · 0⤊ 0⤋