more than Brian. How many does each of them has?
Please, plase help me. Showing the work would be even great!!
2007-10-01 14:21:19 · 18 answers · asked by erikck 2 in Science & Mathematics ➔ Mathematics
2,7,12
2007-10-01 14:25:48 · answer #1 · answered by Alberd 4 · 0⤊ 0⤋
ok lets just say sydney is X, Brian is Y, and Todd is Z.
X + Y + Z = 21
Y = 2X + 3
Z = (2X + 3 + 5 )so just substitute
so X + (2x+3) + (2x +8) = 21
5x +11 = 21
5x=10
x = 2.
substitute x and find y which then equals 7. so that means z = 12. todd has 12 bucks, brian has 7 and sydney has 2. hope this helps. :)
2007-10-01 14:34:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Sydney + Brian + Todd = $21.
x + (3+2x ) + 5 = 21
3x = 21 - 8
3x = 13
x = 13/3
x = 4.33
Therefore : Sydney has $4.33, Brian has 3+2 x4.33 =$11.67, and Todd has $5, total of $21.
2007-10-01 14:31:43 · answer #3 · answered by still 5 · 0⤊ 0⤋
sydney=4 todd=5 brian=12
2007-10-01 14:25:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Todd- $12
Sydney- $2
Brian- $7
guess nad check
start w/ brian having 9 cuz thats the 1st number i think of. then -3 and then divide 2 you get 3 for sydney. that means todd gets 14 cuz 5+9=14. you add all. not right. try 2 for sydney now. x2+3=7 brian=$7. 7=5=12 12+7+2=21...
THERe YOU GO!
:D
SRY IF CONFUSING
2007-10-01 14:29:10 · answer #5 · answered by Janet H 2 · 0⤊ 0⤋
Sydney, Brian, and Todd have $21 in all.
So S+B+T=21
Brian has $3 more than the twice the amount Syney has.
So B=3+2S
Todd has $5
So T=5
So you have:
S+B+T=21
B=3+2S
and T=5
Substitute the easier equations into the more complex ones to resolve B and S.
2007-10-01 14:25:22 · answer #6 · answered by SV 5 · 0⤊ 0⤋
Removing Todd from the calculation. Sydney and Brian have $16. So if S is Sydney's money, 16-S is Brian's money. Moreover............
(16-S) = 3+2*S
Rearranging and dividing, S= 4.33 and Brian=11.67.
2007-10-01 14:27:29 · answer #7 · answered by cattbarf 7 · 0⤊ 0⤋
Sydney has $2.
Brian has $7.
Todd has $12.
:)
2007-10-01 14:31:48 · answer #8 · answered by spiffyllama 2 · 0⤊ 0⤋
TODD HAS $5
21 = 5(todd) + 2x+3(brian) + x(sydney)
21-5 = (2x + 3) + x
16 -3 = 3x
13 = 3x
4.33=x
SO SYDNEY HAS $4.33
2X+3 = 2*4.33 +3 = $11.66
SO BRIAN HAS $11.66
21 = 5 + 11.66 + 4.33
2007-10-01 14:27:16 · answer #9 · answered by Anonymous · 0⤊ 0⤋
The should either buy twenty one dollars worth of candy or go buy the new Queen CD.
Don't listen to the Math teacher. There is plenty of info.
Subtract 5 from 21. What does that leave?
Subtract 3 from what is left above.
Then, divide the other by two.
Add three to that.
This should be enough for you to work it out. Still can't have the answer though
2007-10-01 14:25:15 · answer #10 · answered by Maitreyi 2 · 0⤊ 0⤋
I'm not sure this question is correct? Anyhow, let S, B and T be the people.
T has $5.
So $16 left.
S has $x, so B has $(2x + 3). S + B have $(3x + 3). So $3x = 16 - 3 = 13.
therefore 3x = 13
x = 4.33
T = $5
S = $4.33
B = $11.66
2007-10-01 14:25:57 · answer #11 · answered by Steve 2 · 0⤊ 0⤋