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time vs. position
0--------------- 0
2----------------4
4---------------6.5
6---------------8.5
8---------------14
10-------------14
12-------------14
14-------------14
16-------------14
18-------------14
20-------------14
22-------------11
24------------ 6.2
26-------------0

Try to use the graph above

calculate the average acceleration for the time period t=8 & t=10

draw a vector to show this acceleration

suppose that there is a passenger of mass 70kg in the elevator calculate the apparent weight of the passenger at t=4s

2007-10-01 14:02:24 · 1 answers · asked by Kyle 1 in Science & Mathematics Physics

1 answers

T---- D ---- V
0---- 0----
2---- 4---- 2.00
4---- 6.5---- 1.25
6--- 8.5---- 1.00
8---- 14---- 2.75
10---- 14---- 0.00
12---- 14---- 0.00
14---- 14---- 0.00
16---- 14---- 0.00
18---- 14---- 0.00
20---- 14---- 0.00
22---- 11---- -1.50
24---- 6.2---- -2.40
26---- 0---- -3.10

The change in speed was from

2.75 to 0 m/s from 8 to 10 sec
a=(V2-V1)/(t2-t1)=
a=(0- 2.75)/(10-8)= -1.375m/s^2

2007-10-05 09:24:38 · answer #1 · answered by Edward 7 · 0 0

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