Seventy-two identical banquet dinners cost a total of $_67.9_. (Sorry, I could not remember the first and last digits. ) How much did one dinner cost?
2007-10-01 13:55:05 · 2 answers · asked by big daddy 2 in Science & Mathematics ➔ Mathematics
Even if you didn't remember the first and last digits of the total, you could start at ~$2 x 72 and do price iterations by $0.01 until you get a total that meets the above digt qualifications (i.e 6 in the tens place, 7 in the ones place, 9 in the tenths place, etc.)
I actually did this in MS Excel and got $5.11/dinner, which gives a total of $367.92......even if you didn't want to do this by trial and error, i'm pretty sure the missing digits could be found algebraically in some way
2007-10-01 16:28:10 · answer #1 · answered by The K-Factor 3 · 0⤊ 0⤋
Well, when you eventually remember the original number in its entirety, divide it by 72 to get the unit price.
2007-10-01 21:14:09 · answer #2 · answered by SV 5 · 0⤊ 0⤋