10g of a fuel are burned under a calorimeter containing 200g of H20. The temperature of water increases from 15°C to 55°C. Calculate the total heat produced (in joules) and the heat of combustion per gram of fuel.
THANK YOU!
2007-10-01 13:43:45 · 2 answers · asked by carsmithol 2 in Science & Mathematics ➔ Chemistry
The (small) calorie approximates the energy needed to increase the temperature of 1 gram of water by 1 °C. This is about 4.184 joules.
the total heat produced: 200*(55-15)*4.184 = 33. kJ
the heat of combustion per gram of fuel: 3.3 kJ
2007-10-02 12:07:09 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋
regularly occurring Equations: clever warmth: Q = MC(Delta T) the place M = mass, C=particular Hest, Delta T = temperature substitute warmth of Fusion / Melting: Q = MH the place M = mass, H = warmth of fusion / melting There are 3 stages in contact right here: one million) Ice at -5 C to Ice at 0 C (particular warmth for use is for good via fact it remains in good form) Q = 11.sixty one x 2.09 x (0 - (-5)) = 121.32 J 2) Ice at 0 C to Water at 0 C Q = (11.sixty one / 18.02) x 6.02 x one thousand = 3878.fifty 9 J 3) Water at 0 C to Water at 0.5 C (particular warmth is for water) Q = 11.sixty one x 4.21 x (.5 - 0) = 24.40 3 J entire = 4024.34
2016-12-28 10:17:38 · answer #2 · answered by ? 3 · 0⤊ 0⤋