A car traveling at 91 km/h strikes a tree. The front end of the car compresses and the driver comes to rest af

Question

A car traveling at 91 km/h strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.89 m. What was the average acceleration of the driver during the collision? Express the answer in terms of "g's," where 1.00g = 9.80 m/s2
g

Answer 1

36.62956027 g's

v=91000/3600=25.27777778 meters/second
t=.89*2/25.278=0.070417582 seconds
a=25.27777778/0.070417582 m/s/s =358.9696907
g=358.9696907/9.8=36.62956027

Answer 2

x = at^2/2 = v^2/(2a)
a = v^2/(2x)
Convert v to m/s, calculate a (in m/s^2), convert to g's.