Could someone help me with this math question? I've been trying all day to figure it out. I would really appreciate it thanks.
Tony leaves his house at 10:00 am and drives to his sister’s house. If the drive is at an average speed of 93km/h and the distance between their homes is 238.5 km at what time will he arrive at his sister’s house?
2007-10-01 10:28:13 · 8 answers · asked by ANdrea21 3 in Science & Mathematics ➔ Mathematics
About 12:33:52 (twelve thirty-three and fifty-two seconds). You just divide the distance by the average speed and add it to the starting time, very trivial math really.
2007-10-01 10:32:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Your speed is calculated by taking KM divided by H. So in this case you set 93 km/h= 238.5km / X h and solve for X. So you're going to divide 238.5/93 which equals about 2.56 hours so you add that onto 10:00 am so you'll get there at 12:37 (remember to convert the hours into minutes).
That should be right.. kind of weird that it didn't work out to be a round number though!
2007-10-01 10:37:45 · answer #2 · answered by Steph 2 · 0⤊ 0⤋
238.5 divide by 93 = 2.56 that's time driven in hours
he left at 10 AM so he gets there just after 12:30 PM
2007-10-01 10:34:44 · answer #3 · answered by Mike 7 · 0⤊ 0⤋
238.5 / 93 = 2.5645...
0.5645 of 60 will be about 33.87...
0.87 of 60 is about 52.2...
So, the time he approximately arrived will be:
10 + 2 hours + 33 minutes + 52 seconds
= 12:33:52 PM.
2007-10-04 13:49:09 · answer #4 · answered by acerflea 1 · 0⤊ 0⤋
Total time to travel is 238.5/93 = 2.56 hours
Converting the part of an hour to minutes gives .56 hours x 60 mins = 33.6 mins
So he took 2 hrs 33.6 mins to travel. Add this to the 10am start time and you get 12.34 as his arrival time
2007-10-01 10:33:07 · answer #5 · answered by Anonymous · 0⤊ 0⤋
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2016-09-05 13:57:12 · answer #6 · answered by ? 4 · 0⤊ 0⤋
238.5 km/(93km/h)=time it takes to get there
add that to when he left, but you might have to change the time from hours to minutes
2007-10-01 10:32:29 · answer #7 · answered by Anonymous · 0⤊ 0⤋
12:31
2007-10-01 10:39:46 · answer #8 · answered by jdimes1114 1 · 0⤊ 0⤋