supppose a block of mass 25.0 kg rests on a horizontal plane, and the coefficient of static friction between the surfaces is .220, -what is the max possible static frictional force that could act on the block?___N? -What is the actual static frictional force that acts on the block if an external force of 25.0 N acts horizontally on the block?____N.: please explain how you did these if you could:)
2007-10-01 10:19:38 · 2 answers · asked by nicki s 1 in Science & Mathematics ➔ Physics
Fslip = mgμ (μ being coefficient of friction)
Fslip the max possible Ffric.
If Fext < Fslip, Ffric = Fext.
2007-10-03 12:32:05 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋
If there became no friction the firefighter might enhance up freely at 9.eighty one m/s² . we would desire to subtract this frictional stress from mg to locate the accelerating stress. The accelerating stress = ma = mg - Ff the place Ff is the frictional stress. one hundred sixty X 4 = (one hundred sixty X 9.eighty one) - Ff Ff = (one hundred sixty X 9.eighty one) - one hundred sixty X 4 = one hundred sixty( 9.eighty one - 4) = one hundred sixty X 5.eighty one Ff = 929.6 N Frictional stress appearing is 930 N.
2016-12-28 10:00:13 · answer #2 · answered by ? 3 · 0⤊ 0⤋