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You drive a car 8h at 50 km/h, then 8h at 68km/h.

What is your average velocity? Answer in units of km/h.

2007-10-01 07:39:13 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

you drove the car at 50 Kmph for 8 hours = 400 Km total distance at 50 Kmh
You then drove the car at 68 Kmph for 8 hours = 544 Km total distance at 68 Kmph:

Total over all distance you drove was 400Km + 544 Km = 944 Km

Total driving time is 16 hours:

average speed (velocity) equal to total distance divided by total driving time.

average speed ( velocity) = total distance / total time

Average speed (velocity) = 944 / 16
Average speed (velocity) = 59 Kmph
Here is the kicker. velocity is usually stated in m/s (meters per second) not Km's per hour. Your teacher might be throwing you a curve. So take it one step further as insurance against that.
convert 59 Kmph to m/s just to be sure:

Couple of ways to do this. first conver Kilometers to meters.

easy enough . 1 kilometer = 1,000 meters

simply multipy 59 X 1,000 = 59,000 m/h
now find out how many seconds there are in one hour.

60 minutes in one hour, and 60 seconds in one minute
so
60 (minutes in a hour) X 60 (seconds in a minute) = 3600 seconds in one hour.

Next step to get m/s (meters per second)

59,000 (number of meters going per hour) / 3600 (number of seconds in one hour. = meters per second traveling.

59,000 / 3600 = 16.3888888888 now round off to two decimal places.

59,000 / 3600 = 16.39 m/s
velocity = 16.39 m/s (meters per second)

File this in the back of your mind for future reference: The standard notation for velocity is m/s ( meters per second) unless only wise noted.

2007-10-01 08:11:31 · answer #1 · answered by JUAN FRAN$$$ 7 · 0 1

D1= distance travel in the first period
V1= velocity for the first period
T1= time for the frist period
D2= distance travel in the second period
V2= velocity for the second period
T2= time for the second period
Dt= distance total travel
Tt= total time travel
Vt= average velocity travel

T1*V1= D1
8h *50 km/h = D1
D1 = 400km

D2= T2*V2
D2= 8h *68km/h
D2= 544 km

Dt= D1 + D2
Dt= 400 km +544vkm
Dt= 944 km

Tt = T1 + T2
Tt = 8h + 8 h
Tt = 16h

Vt= Dt/Tt
Vt = 944 km / 16 h
Vt = 59 km/h

2007-10-01 07:49:45 · answer #2 · answered by Anonymous · 0 0

This is a simple math question, not physics.

You drove both speeds for the same amount of time so the answer is just the average of the two speeds,

50 + 68 = 118
118 / 2 = 59km/h

2007-10-01 07:42:58 · answer #3 · answered by suspendedagain300 6 · 0 0

I will give you the answer, but if you try 'turning it in' without the 'work' you'll probably 'fail' ... so see if you can 'figure out' how I got the answer, okay?
59km/h is the 'average velocity' ...

2007-10-01 07:45:12 · answer #4 · answered by Kris L 7 · 0 0

No, emails are sending-- you will possibly purely ought to attend slightly. MA: "Longview" Greenday (that is approximately boredom/laziness-- no longer something to do. And.. uh-- what adult males do while they're bored).

2016-11-06 23:15:23 · answer #5 · answered by Anonymous · 0 0

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