...is dissolved in water and treated with an excess of AgNO3. If the mass of the AgBr precipitate that forms is 0.6064 g, what is the percent by mass of Br in the original compound? = ___%?
2007-10-01 07:38:39 · 2 answers · asked by eclipsegt_01_03 2 in Science & Mathematics ➔ Chemistry
AgNO3 + Br- ===> AgBr(s) + NO3-
Atomic weights: Ag=108 Br=80 AgBr=188
0.6064gAgBr x 1molAgBr/188gAgBr x 1molBr-/1molAgBr x 80gBr-/1molBr- = 0.2580g Br-
0.2580/03220 x 100% = 80.14%
2007-10-01 07:46:52 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
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2016-12-14 04:52:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋