alright, I forgot these last problems and I can't figure them out
(same rules as these questions:)http://answers.yahoo.com/question/index;_ylt=Ahzt3JUUy9_N5MrpVr.XFizsy6IX;_ylv=3?qid=20071001094901AAfmDsu
if f(x) equals [square root](x-1) and g(x) equals [square root] (4-x) find f(g(2))
also...
2007-10-01 06:35:54 · 4 answers · asked by Kremer 4 in Science & Mathematics ➔ Mathematics
okay so f(g)= sq.rt.((sq.rt. 4-x)-1)
that is f(g(x))= [(4-x)^1/2 -1]^1/2
so f(g(2))= [(4-2)^1/2 -1]^1/2
that is (2^1/2 -1)^1/2
2^1/4 - 1^1/2
2^1/4 - 1. i don't think it can be simplified more than that.
2007-10-01 06:54:22 · answer #1 · answered by Nilly 3 · 0⤊ 0⤋
f(g(2)) = [square root]([square root}(4-2)-1)
Lets make our square roots power to the 1/2
f(g(2))=((2)^1/2)^1/2
f(g(2))=2^1/4
or
f(g(2))=[fourthroot of 2]
2007-10-01 06:45:46 · answer #2 · answered by Arin 3 · 0⤊ 0⤋
I wish i could help, but I last did math like this 20 years ago in college, haven't had a need for it since. Wonder what all the fuss was about to learn it?!
2007-10-01 06:43:45 · answer #3 · answered by Anonymous · 0⤊ 1⤋
f(x) = sqrt(x-1)
g(x) = sqrt(4-x)
g(2) sqrt(4-2) = sqrt(2)
f(g(2)) = sqrt(sqrt(2)-1))
also what ????
2007-10-01 06:45:55 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋