The decimal equivalent of ( a u b ) n c.?

Question

A 0 0 0 0 1 1 1 1
B 0 0 1 1 0 0 1 1
C 0 1 0 1 0 1 0 1
plz explain and solve it..

Answer 1

I'm not sure if I understand what you're shooting for, but I'm taking the u and n to be the bitwise "or" and "and" operators, respectively. (These operators are used primarily, as far as I've seen, in computer programming; "bitwise" just means we determine each "bit", or binary digit, on its own.) Then, bitwise, we take AuB to be 1 if either A or B (or both) is 1, 0 if neither A nor B is 1:
AuB = 00111111

Now, bitwise, (AuB)nC is 1 if both AuB and C are 1, 0 if either AuB or C (or both) is 0:
(AuB)nC = 00010101.

Now, the decimal equivalent is just the base-ten equivalent of this number, or
2^4 + 2^2 + 2^0 = 16 + 4 + 1 = 21.

Answer 2

Hi. This is binary. Each 1 or 0 represents whether or not that power of 2 is included in the number. C is 85. There are converters on line http://acc6.its.brooklyn.cuny.edu/~gurwitz/core5/nav2tool.html but you really just need to understand once how the conversion works. http://www.newton.dep.anl.gov/newton/askasci/1995/math/MATH065.HTM

Answer 3

A is binary for 15 decimal
B is binary decimal for 51 decimal
C is binary decimal for 85 decimal

If you mean (A U B) intersection C, then it is { }